Mechanical Properties of Solids

Question: The area of cross-section of a wire of length $1.1$ metre is $1 mm^2$. It is loaded with 1 kg. If Young's modulus of copper is $1.1\times {{10}^{11}}\,N/{{m}^{2}}$, then the increase in length will be (If $g=10\,m/{{s}^{2}})$



1) 0.01 mm
2) 0.075 mm
3) 0.1 mm
4) 0. 15 mm
Solution: Explanation: No Explanation
Young’s Modulus Breaking Stress

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