Categories > differentiation > Implicit-function > If $y = \frac{{\sqrt x {{(2x + 3)}^2}}}{{\sqrt {x + 1} }},$then $\frac{{dy}}{{dx}} = $

differentiation

Question: If $y = \frac{{\sqrt x {{(2x + 3)}^2}}}{{\sqrt {x + 1} }},$then $\frac{{dy}}{{dx}} = $


1) $y{\rm{ }}\left[ {\frac{1}{{2x}} + \frac{4}{{2x + 3}} - \frac{1}{{2(x + 1)}}} \right]$
2) $y{\rm{ }}\left[ {\frac{1}{{3x}} + \frac{4}{{2x + 3}} + \frac{1}{{2(x + 1)}}} \right]$
3) $y{\rm{ }}\left[ {\frac{1}{{3x}} + \frac{4}{{2x + 3}} + \frac{1}{{x + 1}}} \right]$
4) None of these
Solution: Explanation: Explanation
Implicit-function

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)

Previous Question Next Question

Related Questions