differentiation

Question: If ${2^x} + {2^y} = {2^{x + y}}$, then $\frac{{dy}}{{dx}} = $



1) ${2^{x - y}}\frac{{{2^y} - 1}}{{{2^x} - 1}}$
2) ${2^{x - y}}\frac{{{2^y} - 1}}{{1 - {2^x}}}$
3) $\frac{{{2^x} + {2^y}}}{{{2^x} - {2^y}}}$
4) None of these
Solution: Explanation: Explanation
Implicit-function

Rate this question:

Average rating: (0 votes)

Previous Question Next Question