differentiation

Question: If $y = {x^x}$, then $\frac{{dy}}{{dx}} = $



1) ${x^x}\log ex$
2) ${x^x}\left( {1 + \frac{1}{x}} \right)$
3) $(1 + \log x)$
4) ${x^x}\log x$
Solution: Explanation: Explanation
Implicit-function

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