differentiation

Question: If $x = \frac{{2\,t}}{{1 + {t^2}}},\,\,y = \frac{{1 - {t^2}}}{{1 + {t^2}}},$then $\frac{{d\,y}}{{d\,x}}$ equals



1) $\frac{{2\,t}}{{{t^2} + 1}}$
2) $\frac{{2\,t}}{{{t^2} - 1}}$
3) $\frac{{2\,t}}{{1 - {t^2}}}$
4) None of these
Solution: Explanation: Explanation
Implicit-function

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