Ray Optics and Optical Instruments

Question: Angle of deviation $(\delta $) by a prism (refractive index = $\mu $ and supposing the angle of prism A to be small) can be given by

1) $\delta =(\mu -1)\,A$

2) $\delta =(\mu +1)\,A$

3) $\delta =\frac{\sin \frac{A+\delta }{2}}{\sin \frac{A}{2}}$

4) $\delta =\frac{\mu -1}{\mu +1}A$

Solution:

Explanation: No Explanation

Prism Theory & Dispersion of Light

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)