differentiation

Question: Let $y = {t^{10}} + 1$and $x = {t^8} + 1,$then $\frac{{{d^2}y}}{{d{x^2}}}$is

1) $\frac{5}{2}t$

2) $20{t^8}$

3) $\frac{5}{{16{t^6}}}$

4) None of these

Solution:

Explanation: Explanation

Implicit-function

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