differentiation

Question: Let $g(x)$ be the inverse of the function $f(x)$ and $f'(x) = \frac{1}{{1 + {x^3}}}$. Then $g'(x)$ is equal to



1) $\frac{1}{{1 + {{(g(x))}^3}}}$
2) $\frac{1}{{1 + {{(f(x))}^3}}}$
3) $1 + {(g(x))^3}$
4) $1 + {(f(x))^3}$
Solution: Explanation: Explanation
Implicit-function

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