differentiation

Question: If ${x^3} + 8xy + {y^3} = 64$,then $\frac{{dy}}{{dx}} = $



1) $ - \frac{{3{x^2} + 8y}}{{8x + 3{y^2}}}$
2) $\frac{{3{x^2} + 8y}}{{8x + 3{y^2}}}$
3) $\frac{{3x + 8{y^2}}}{{8{x^2} + 3y}}$
4) None of these
Solution: Explanation: Explanation
Implicit-function

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