Ray Optics and Optical Instruments

Question: If the wavelength of light in vacuum be $\lambda$, the wavelength in a medium of refractive index $n$ will be

1) $n \lambda$

2) $\frac{\lambda }{n}$

3) $\frac{\lambda }{{{n}^{2}}}$

4) $n^2\lambda$

Solution:

Explanation: No Explanation

Refraction of Light at Plane Surfaces

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