differentiation

Question: If $x = \frac{{1 - {t^2}}}{{1 + {t^2}}}$and $y = \frac{{2at}}{{1 + {t^2}}}$, then $\frac{{dy}}{{dx}} = $

1) $\frac{{a(1 - {t^2})}}{{2t}}$

2) $\frac{{a({t^2} - 1)}}{{2t}}$

3) $\frac{{a({t^2} + 1)}}{{2t}}$

4) $\frac{{a({t^2} - 1)}}{t}$

Solution:

Explanation: Explanation

Implicit-function

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