electrochemistry

Question: Calculate the useful work done during the reaction $Ag\,(s)+\frac{1}{2}C{{l}_{2}}(g)\to AgCl\,(s)$ Given that $E_{C{{l}_{2}}/C{{l}^{-}}}^{0}=+1.36V$ and $E_{AgCl,\,Ag,\,C{{l}^{-}}}^{0}=+0.220V$ if ${{P}_{C{{l}_{2}}}}=1$ and T = 298K



1) $110\,kJ\,mo{{l}^{-1}}$
2) $220\,kJ\,mo{{l}^{-1}}$
3) $55\,kJ\,mo{{l}^{-1}}$
4) $100\,kJ\,mo{{l}^{-1}}$
Solution: Explanation: No Explanation
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