electrochemistry

Question: The emf of the cell in which the following reaction $Zn(s)+N{{i}^{2+}}(a=1.0)$? $Z{{n}^{2+}}(a=10)+Ni\,(s)$ occurs, is found to be 0.5105 V at 298K. The standard emf of the cell is

1) 0.5400V

2) 0.4810 V

3) 0.5696 V

4) – 0.5105 V

Solution:

Explanation: No Explanation

Electrode potential Ecell Nernst equation and ECS

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