electrochemistry

Question: A solution containing one mole per litre of each $Cu{{(N{{O}_{3}})}_{2}},\,AgN{{O}_{3}},\,H{{g}_{2}}{{(N{{O}_{3}})}_{2}}$ and $Mg{{(N{{O}_{3}})}_{2}}$, is being electrolysed by using inert electrodes. The values of standard electrode potentials in volts (reduction potentials) are $Ag/A{{g}^{+}}=+0.80,$ $2Hg/Hg_{2}^{2+}=+0.79,$ $Cu/C{{u}^{2+}}=+0.34,\,Mg/M{{g}^{2+}}=-2.37$ with increasing voltage, the sequence of deposition of metals on the cathode will be



1) $Ag, Hg, Cu, Mg$
2) $Mg, Cu, Hg, Ag$
3) $Ag, Hg, Cu$
4) $Cu, Hg, Ag$
Solution: Explanation: No Explanation
Electrode potential Ecell Nernst equation and ECS

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