Consider the reaction $M_{(aq)}^{n+}+n{{e}^{-}} o {{M}_{(s)}}$. The standard reduction potential values of the elements ${{M}_{1}},\,{{M}_{2}}$ and ${{M}_{3}}$ are – 0.34 V, – 3.05 V and – 1.66 V respectively. The order of their reducing power will be

Question

Consider the reaction $M_{(aq)}^{n+}+n{{e}^{-}}	o {{M}_{(s)}}$. The standard reduction potential values of the elements ${{M}_{1}},\,{{M}_{2}}$ and ${{M}_{3}}$ are – 0.34 V, – 3.05 V and – 1.66 V respectively. The order of their reducing power will be

Accepted Answer

${{M}_{2}}>{{M}_{3}}>{{M}_{1}}$

Answer

${{M}_{1}}>{{M}_{2}}>{{M}_{3}}$

Answer

${{M}_{3}}>{{M}_{2}}>{{M}_{1}}$

Answer

${{M}_{1}}>{{M}_{3}}>{{M}_{2}}$

electrochemistry

Question: Consider the reaction $M_{(aq)}^{n+}+n{{e}^{-}}\to {{M}_{(s)}}$. The standard reduction potential values of the elements ${{M}_{1}},\,{{M}_{2}}$ and ${{M}_{3}}$ are – 0.34 V, – 3.05 V and – 1.66 V respectively. The order of their reducing power will be

electrochemistry

Question: Consider the reaction $M_{(aq)}^{n+}+n{{e}^{-}}\to {{M}_{(s)}}$. The standard reduction potential values of the elements ${{M}_{1}},\,{{M}_{2}}$ and ${{M}_{3}}$ are – 0.34 V, – 3.05 V and – 1.66 V respectively. The order of their reducing power will be

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