Categories > electrochemistry > Electrode potential > $Emf$ of cell $Ni|N{{i}^{2+}}(1.0M)||A{{u}^{3+}}(1.0M)|Au$ (where ${{E}^{0}}$ for $N{{i}^{2+}}|Ni$ is – 0.25 V; ${{E}^{0}}$ for $A{{u}^{3+}}|Au$ is 1.50 V) is

electrochemistry

Question: $Emf$ of cell $Ni|N{{i}^{2+}}(1.0M)||A{{u}^{3+}}(1.0M)|Au$ (where ${{E}^{0}}$ for $N{{i}^{2+}}|Ni$ is – 0.25 V; ${{E}^{0}}$ for $A{{u}^{3+}}|Au$ is 1.50 V) is


1) + 125 V
2) – 1.75 V
3) + 1.75 V
4) + 4.0 V
Solution: Explanation: No Explanation
Electrode potential Ecell Nernst equation and ECS

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