electrochemistry

Question: The correct representation of Nernst’s equation is

1) ${{E}_{{{M}^{n+}}/M}}={{E}^{0}}_{{{M}^{n+}}/M}+\frac{0.0591}{n}\log ({{M}^{n+}})$

2) ${{E}_{{{M}^{n+}}/M}}={{E}^{0}}_{{{M}^{n+}}/M}-\frac{0.0591}{n}\log ({{M}^{n+}})$

3) ${{E}_{{{M}^{n+}}/M}}={{E}^{0}}_{{{M}^{n+}}/M}+\frac{n}{0.0591}\log ({{M}^{n+}})$

4) None of these

Solution:

Explanation: No Explanation

Electrode potential Ecell Nernst equation and ECS

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