If $x = \exp \left\{ {{{ an }^{ - 1}}\left( {\frac{{y - {x^2}}}{{{x^2}}}} ight)} ight\}\,\,$, then $\frac{{dy}}{{dx}}$ equals

Question

If $x = \exp \left\{ {{{	an }^{ - 1}}\left( {\frac{{y - {x^2}}}{{{x^2}}}} ight)} ight\}\,\,$, then $\frac{{dy}}{{dx}}$ equals

Accepted Answer

$2x\,[1 + 	an \,(\log x)] + x{\sec ^2}(\log x)$

Answer

$x\,[1 + 	an \,(\log x)] + {\sec ^2}(\log x)$

Answer

$2x\,[1 + 	an \,(\log x)] + {x^2}\,\,{\sec ^2}(\log x)$

Answer

$2x\,[1 + 	an \,(\log x)] + {\sec ^2}(\log x)$

differentiation