electrochemistry

Question: Equivalent conductance of saturated $BaS{{O}_{4}}$ is $400\,Oh{{m}^{-1}}\,c{{m}^{2}}\,equi{{v}^{-1}}$ and specific conductance is $8 imes {{10}^{-5}}\,Oh{{m}^{-1}}\,c{{m}^{-1}}$. Hence ${{K}_{sp}}$ of $BaS{{O}_{4}}$ is



1) $4\times {{10}^{-8}}\,{{M}^{2}}$
2) $1\times {{10}^{-8}}\,{{M}^{2}}$
3) $4\times {{10}^{-8}}\,{{M}^{2}}$
4) $1\times {{10}^{-8}}\,{{M}^{2}}$
Solution: Explanation: No Explanation
Conductors and Conductance

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