For pure water degree of dissociation of water is $1.9 imes {{10}^{-9}}$, $\Lambda _{m}^{\infty }({{H}^{+}})=350\,S\,c{{m}^{2}}\,mo{{l}^{-1}}$ $\Lambda _{m}^{\infty }(O{{H}^{-}})=200\,S\,c{{m}^{2}}\,mo{{l}^{-1}}$ hence, molar conductance of water is

Question

For pure water degree of dissociation of water is $1.9	imes {{10}^{-9}}$, $\Lambda _{m}^{\infty }({{H}^{+}})=350\,S\,c{{m}^{2}}\,mo{{l}^{-1}}$ $\Lambda _{m}^{\infty }(O{{H}^{-}})=200\,S\,c{{m}^{2}}\,mo{{l}^{-1}}$ hence, molar conductance of water is

Accepted Answer

$1.045	imes {{10}^{-6}}\,S\,c{{m}^{2}}\,mo{{l}^{-1}}$

Answer

$1.045	imes {{10}^{-9}}\,S\,c{{m}^{2}}\,mo{{l}^{-1}}$

Answer

$1.04	imes {{10}^{-14}}\,S\,c{{m}^{2}}\,mo{{l}^{-1}}$

electrochemistry

Question: For pure water degree of dissociation of water is $1.9\times {{10}^{-9}}$, $\Lambda _{m}^{\infty }({{H}^{+}})=350\,S\,c{{m}^{2}}\,mo{{l}^{-1}}$ $\Lambda _{m}^{\infty }(O{{H}^{-}})=200\,S\,c{{m}^{2}}\,mo{{l}^{-1}}$ hence, molar conductance of water is

electrochemistry

Question: For pure water degree of dissociation of water is $1.9\times {{10}^{-9}}$, $\Lambda _{m}^{\infty }({{H}^{+}})=350\,S\,c{{m}^{2}}\,mo{{l}^{-1}}$ $\Lambda _{m}^{\infty }(O{{H}^{-}})=200\,S\,c{{m}^{2}}\,mo{{l}^{-1}}$ hence, molar conductance of water is

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