electrochemistry

Question: The equivalent conductance of an acetic acid solution of concentration 0.01 M is $1.65\,m\,S\,{{m}^{2}}\,mo{{l}^{-1}}$ at 298 K. The dissociation constant of acetic acid at this temperature is (given, ${{\Lambda }_{0}}=39.0\,m\,S\,{{m}^{2}}\,mo{{l}^{-1}}$)



1) $1.8\times {{10}^{-4}}$
2) $4.0\times {{10}^{-10}}$
3) $1.8\times {{10}^{-5}}$
4) $1.8\times {{10}^{-6}}$
Solution: Explanation: No Explanation
Conductors and Conductance

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