electrochemistry

Question: The expression $\alpha =\Lambda /{{\Lambda }_{0}}$ will not hold good for the electrolyte



1) $HOCN$
2) ${{H}_{2}}S{{O}_{4}}$
3) $C{{H}_{3}}C{{H}_{2}}OH$
4) $C{{H}_{3}}C{{O}_{2}}H$
Solution: Explanation: No Explanation
Conductors and Conductance

Rate this question:

Average rating: (0 votes)

Previous Question Next Question