electrochemistry

Question: The number of electrons passing per second through a cross-section of copper wire carrying $10^{–6}$ Amperes of current per second is found to be

1) $1.6\times {{10}^{-19}}$

2) $6\times {{10}^{-35}}$

3) $6\times {{10}^{-16}}$

4) $6\times {{10}^{12}}$

Solution:

Explanation: No Explanation

Faraday's Laws of electrolysis

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