electrochemistry

Question: A conducting wire carries a current of $0.965$ Ampere. Rate of flow of electrons per second at a given point is

1) $1\times {{10}^{-5}}\,\,\,{{N}_{0}}$

2) $N_0$

3) $0.965 N_0$

4) $\frac{{{N}_{0}}}{0.965}$

Solution:

Explanation: No Explanation

Faraday's Laws of electrolysis

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