differentiation

Question: $\frac{d}{{dx}}\left[ {\left( {\frac{{{{\tan }^2}2x - {{\tan }^2}x}}{{1 - {{\tan }^2}2x{{\tan }^2}x}}} \right)\cot 3x} \right]$

1) $\tan 2x\,\tan x$

2) $\tan 3x\tan x$

3) ${\sec ^2}x$

4) $\sec x\tan x$

Solution:

Explanation: Explanation

standard-differentiation

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