electrochemistry

Question: Electrochemical equivalent of $Cu$ in the reaction, $Cu^{2+}+2e^– \to Cu$ is

1) $\frac{63.5}{96.500}$

2) $\frac{63.5}{96500\times 2}$

3) $\frac{63.5\times 2}{96500}$

4) $\frac{96500}{63.5\times 2}$

Solution:

Explanation: No Explanation

Faraday's Laws of electrolysis

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