electrochemistry

Question: A steady current of 3.0 A for 1 hour corresponds to a passage of

1) $1.08 \times 10^5$ C

2) $0.11$ F

3) $1.08 \times 10^4$ electrons

4) $1.51$ V

Solution:

Explanation: No Explanation

Faraday's Laws of electrolysis

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