solutions

Question: How many moles of glucose should be added to 1000 g of water so that the freezing point is depressed by 0.93 K ? Assume ${{K}_{f}}$ for water to be 1.86 K Kg$mo{{l}^{-1}}$

1) 0.5

2) 2.0

3) $3.5\times {{10}^{-4}}$

4) $2\times {{10}^{-3}}$

Solution:

Explanation: No Explanation

Colligative properties

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