A 0.001 molal solution of $\left[ Pt{{(N{{H}_{3}})}_{4}}C{{l}_{4}} \right]$in water had a freezing point depression of 0.0054°C. If ${{K}_{f}}$for water is 1.80, the correct formulation for the above molecule is

Question

Accepted Answer

$\left[ Pt{{(N{{H}_{3}})}_{4}}C{{l}_{2}} \right]\,Cl$

Answer

$\left[ Pt{{(N{{H}_{3}})}_{4}}C{{l}_{3}} \right]\,Cl$

Answer

$\left[ Pt{{(N{{H}_{3}})}_{4}}C{{l}_{2}} \right]\,C{{l}_{3}}$

Answer

$\left[ Pt{{(N{{H}_{3}})}_{4}}C{{l}_{4}} \right]\,$

solutions

Question: A 0.001 molal solution of $\left[ Pt{{(N{{H}_{3}})}_{4}}C{{l}_{4}} \right]$in water had a freezing point depression of 0.0054°C. If ${{K}_{f}}$for water is 1.80, the correct formulation for the above molecule is

solutions

Question: A 0.001 molal solution of $\left[ Pt{{(N{{H}_{3}})}_{4}}C{{l}_{4}} \right]$in water had a freezing point depression of 0.0054°C. If ${{K}_{f}}$for water is 1.80, the correct formulation for the above molecule is

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