solutions

Question: The molal freezing point constant for water is 1.86°C /mol. If 342 gm of cane sugar $({{C}_{12}}{{H}_{22}}{{O}_{11}})$ are dissolved in 1000 g of water, the solution will freeze at



1) – 1.86° C
2) 1.86° C
3) – 3.92° C
4) 2.42° C
Solution: Explanation: No Explanation
Colligative properties

Rate this question:

Average rating: (0 votes)

Previous Question Next Question