differentiation

Question: If $y = {e^x}\log x$, then $\frac{{dy}}{{dx}}$is

1) $\frac{{{e^x}}}{x}$

2) ${e^x}\left( {\frac{1}{x} + x\log x} \right)$

3) ${e^x}\left( {\frac{1}{x} + \log x} \right)$

4) $\frac{{{e^x}}}{{\log x}}$

Solution:

Explanation: Explanation

standard-differentiation

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