solutions

Question: The freezing points of equimolar solutions of glucose, $KN{{O}_{3}}$ and $AlC{{l}_{3}}$ are in the order of

1) $AlC{{l}_{3}} < KN{{O}_{3}} < Glucose$

2) $Glucose < KN{{O}_{3}} < AlC{{l}_{3}}$

3) $Glucose < AlC{{l}_{3}} < KN{{O}_{3}}$

4) $AlC{{l}_{3}} < Glucose < KN{{O}_{3}}$

Solution:

Explanation: No Explanation

Colligative properties

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