Categories > solutions > Ideal and Non-ideal solution > The vapour pressure of a solvent decreased by $10\ mm$ of mercury, when a non-volatile solute was added to the solvent. The mole fraction of the solute in the solution is 0.2. What should be the mole fraction of the solvent, if decrease in the vapour pressure is to be $20\ mm$ of mercury

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Question: The vapour pressure of a solvent decreased by $10\ mm$ of mercury, when a non-volatile solute was added to the solvent. The mole fraction of the solute in the solution is 0.2. What should be the mole fraction of the solvent, if decrease in the vapour pressure is to be $20\ mm$ of mercury


1) 0.8
2) 0.6
3) 0.4
4) 0.2
Solution: Explanation: No Explanation
Ideal and Non-ideal solution Azeotropic mixture and Raoult’s law

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