differentiation

Question: If $y = {\sin ^{ - 1}}\sqrt x $, then $\frac{{dy}}{{dx}} = $



1) $\frac{2}{{\sqrt x \sqrt {1 - x} }}$
2) $\frac{{ - 2}}{{\sqrt x \sqrt {1 - x} }}$
3) $\frac{1}{{2\sqrt x \sqrt {1 - x} }}$
4) $\frac{1}{{\sqrt {1 - x} }}$
Solution: Explanation: Explanation
standard-differentiation

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