solutions

Question: The volume of 95% ${{H}_{2}}S{{O}_{4}}$$\text{(density}=1.85\,c{{m}^{-3}}\text{)}$ needed to prepare $100\,c{{m}^{3}}$of 15% solution of ${{H}_{2}}S{{O}_{4}}$$\text{(density}=1.10\,c{{m}^{-3}}\text{)}$ will be



1) 5 cc
2) 7.5 cc
3) 9.4 cc
4) 12.4 cc
Solution: Explanation: No Explanation
Methods of expressing concentration of solution

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