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Question: The amount of ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$( eq. Wt. 49.04) required to prepare 100 ml of its 0.05 N solution is



1) 2.9424 g
2) 0.4904 g
3) 1.4712 g
4) 0.2452 g
Solution: Explanation: No Explanation
Methods of expressing concentration of solution

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