Categories > differentiation > standard-differentiation > If $y = \frac{{{{\sin }^{ - 1}}x}}{{\sqrt {1 - {x^2}} }}$, then $(1 - {x^2})\frac{{dy}}{{dx}}$ is equal to

differentiation

Question: If $y = \frac{{{{\sin }^{ - 1}}x}}{{\sqrt {1 - {x^2}} }}$, then $(1 - {x^2})\frac{{dy}}{{dx}}$ is equal to


1) $x + y$
2) $1 + xy$
3) 1– xy
4) $xy - 2$
Solution: Explanation: Explanation
standard-differentiation

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