differentiation

Question: $\frac{d}{{dx}}\left\{ {\log \left( {\frac{{{e^x}}}{{1 + {e^x}}}} \right)} \right\} = $



1) $\frac{1}{{1 - {e^x}}}$
2) $ - \frac{1}{{1 + {e^x}}}$
3) $ - \frac{1}{{1 - {e^x}}}$
4) None of these
Solution: Explanation: Explanation
standard-differentiation

Rate this question:

Average rating: (0 votes)

Previous Question Next Question