Alternating Current

Question: In an ac circuit, the r.m.s. value of current, $I_rms$ is related to the peak current, I0 by the relation

1) ${I_{rms}} = \frac{1}{\pi }{I_0}$

2) ${I_{rms}} = \frac{1}{{\sqrt 2 }}{I_0}$

3) ${I_{rms}} = \sqrt 2 {I_0}$

4) ${I_{rms}} = \pi {I_0}$

Solution:

Explanation: No Explanation

Alternating Current Voltage Power

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