Alternating Current

Question: The peak value of an alternating e.m.f. E is given by $E = {E_0}\cos \omega \,t$ is 10 volts and its frequency is $50 Hz$. At time $t = \frac{1}{{600}}sec$, the instantaneous e.m.f. is



1) $10 V$
2) $5\sqrt 3 \,V$
3) $5 V$
4) $1 V$
Solution: Explanation: No Explanation
Alternating Current Voltage Power

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