differentiation

Question: If $y = \sin \left( {\frac{{1 + {x^2}}}{{1 - {x^2}}}} \right)$, then $\frac{{dy}}{{dx}} = $

1) $\frac{{4x}}{{1 - {x^2}}}.\cos \left( {\frac{{1 + {x^2}}}{{1 - {x^2}}}} \right)$

2) $\frac{x}{{{{(1 - {x^2})}^2}}}.\cos \left( {\frac{{1 + {x^2}}}{{1 - {x^2}}}} \right)$

3) $\frac{x}{{(1 - {x^2})}}.\cos \left( {\frac{{1 + {x^2}}}{{1 - {x^2}}}} \right)$

4) $\frac{{4x}}{{{{(1 - {x^2})}^2}}}.\cos \left( {\frac{{1 + {x^2}}}{{1 - {x^2}}}} \right)$

Solution:

Explanation: Explanation

standard-differentiation

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