Categories > emi > Motional EMF > A circular metal plate of radius R is rotating with a uniform angular velocity $\omega $ with its plane perpendicular to a uniform magnetic field B. Then the emf developed between the centre and the rim of the plate is

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Question: A circular metal plate of radius R is rotating with a uniform angular velocity $\omega $ with its plane perpendicular to a uniform magnetic field B. Then the emf developed between the centre and the rim of the plate is


1) $\pi \omega B{R^2}$
2) $\omega B{R^2}$
3) $\pi \omega B{R^2}/2$
4) $\omega B{R^2}/2$
Solution: Explanation: No Explanation
Motional EMF

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