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Question: A conducting rod of length l is falling with a velocity v perpendicular to a uniform horizontal magnetic field B. The potential difference between its two ends will be

1) $2Blv$

2) $Blv$

3) $\frac{1}{2}Blv$

4) ${B^2}{l^2}{v^2}$

Solution:

Explanation: No Explanation

Motional EMF

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