differentiation

Question: If $y = {x^2}\log x + \frac{2}{{\sqrt x }},$ then $\frac{{dy}}{{dx}} = $



1) $x + 2x\log x - \frac{1}{{\sqrt x }}$
2) $x + 2x\log x - \frac{1}{{{x^{3/2}}}}$
3) $x + 2x\log x - \frac{2}{{{x^{3/2}}}}$
4) None of these
Solution: Explanation: Explanation
standard-differentiation

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