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Question: A copper disc of radius 0.1 m is rotated about its centre with 10 revolutions per second in a uniform magnetic field of 0.1 Tesla with its plane perpendicular to the field. The e.m.f. induced across the radius of disc is



1) $\frac{\pi }{{10}}\;V$
2) $\frac{{2\pi }}{{10}}\;V$
3) $\pi \times {10^{ - 2}}V$
4) $2\pi \times {10^{ - 2}}V$
Solution: Explanation: No Explanation
Motional EMF

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