Categories > magnetism > Magnetic Equipment > A magnet freely suspended in a vibration magnetometer makes 10 oscillations per minute at a place A and 20 oscillations per minute at a place B. If the horizontal component of earth’s magnetic field at A is $36 \times {10^{ - 6}}T,$ then its value at B is

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Question: A magnet freely suspended in a vibration magnetometer makes 10 oscillations per minute at a place A and 20 oscillations per minute at a place B. If the horizontal component of earth’s magnetic field at A is $36 \times {10^{ - 6}}T,$ then its value at B is


1) $36 \times 10^{–6} T$
2) $72 \times 10^{–6} T$
3) $144 \times 10^{–6} T$
4) $288 \times 10^{–6} T$
Solution: Explanation: No Explanation
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