magnetism

Question: A small bar magnet A oscillates in a horizontal plane with a period T at a place where the angle of dip is $60^o$. When the same needle is made to oscillate in a vertical plane coinciding with the magnetic meridian, its period will be



1) $\frac{T}{{\sqrt 2 }}$
2) $T$
3) $\sqrt 2 T$
4) $2T$
Solution: Explanation: No Explanation
Magnetic Equipment

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