differentiation

Question: If $y = {\tan ^{ - 1}}\frac{{4x}}{{1 + 5{x^2}}} + {\tan ^{ - 1}}\frac{{2 + 3x}}{{3 - 2x}}$, then $\frac{{dy}}{{dx}} = $



1) $\frac{1}{{1 + 25{x^2}}} + \frac{2}{{1 + {x^2}}}$
2) $\frac{5}{{1 + 25{x^2}}} + \frac{2}{{1 + {x^2}}}$
3) $\frac{5}{{1 + 25{x^2}}}$
4) $\frac{1}{{1 + 25{x^2}}}$
Solution: Explanation: Explanation
standard-differentiation

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