magnetism

Question: Moment of inertia of a magnetic needle is 40 gm-cm2 has time period 3 seconds in earth's horizontal field = $3.6 imes {10^{ - 5}}$weber/m2. Its magnetic moment will be

1) $0.5\,A \times {m^2}$

2) $5\,A \times {m^2}$

3) $0.250\,A \times {m^2}$

4) $5 \times {10^2}A \times {m^2}$

Solution:

Explanation: No Explanation

Magnetic Equipment

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