differentiation

Question: If $y = \sqrt {(1 - x)(1 + x)} $, then



1) $(1 - {x^2})\frac{{dy}}{{dx}} - xy = 0$
2) $(1 - {x^2})\frac{{dy}}{{dx}} + xy = 0$
3) $(1 - {x^2})\frac{{dy}}{{dx}} - 2xy = 0$
4) $(1 - {x^2})\frac{{dy}}{{dx}} + 2xy = 0$
Solution: Explanation: Explanation
standard-differentiation

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